/*
If we calculate a2 mod 6 for 0 ≤ a ≤ 5 we get: 0,1,4,3,4,1.


The largest value of a such that a2 ≡ a mod 6 is 4.
Let's call M(n) the largest value of a &lt; n such that a2 ≡ a (mod n).
So M(6) = 4.


Find ∑M(n) for 1 ≤ n ≤ 107.

Anser:
Time:
*/
package main

import (
	"fmt"
	"time"
)

func main() {
	tstart := time.Now()



	tend := time.Now()
	fmt.Println(tend.Sub(tstart))
}